log a²/b² =12 . maka log ³√b/a
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log a²/b² =12 . maka log ³√b/a
1 Jawaban
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1. Jawaban Windya21
log a²/b² = 12 = log (a/b)² = 2 log (a/b)
2 ( log a - log b ) = 12
log a - log b = 12
log ³√b/a = log (b/a)^1/3
= 1/3 log b/a
= 1/3 (log b - log a)
= 1/3 (-12)
= -4