tolong bantu dengan cara kak.. plisss

jawaban: B...
[tex]lim \:( x - > \infty) \frac{4x - 5}{ \sqrt{4 {x}^{2} - x - 3 } } \times \frac{ \frac{1}{x} }{ \frac{1}{x} } \\ = lim \: (x - > \infty ) \frac{ \frac{4x}{x} - \frac{5}{x} }{ \sqrt{ \frac{4 {x}^{2} }{ {x}^{2} } - \frac{x}{ {x}^{2} } - \frac{3}{x} } } \\ = \frac{4 - 0}{ \sqrt{4 - 0 - 0} } = \frac{4}{2} = 2[/tex]