kak tolong bantu soal ini, please

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[tex]2) \\ {3}^{x - 2} = ( \frac{1}{3} ) ^{x + 2} \\ {3}^{x - 2} = ( { 3}^{ - 1} )^{x + 2} \\ {3}^{x - 2} = {3}^{ - x - 2} \\ x - 2 = - x - 2 \\ x + x - 2 + 2 = 0 \\ 2x + 0 = 0 \\ x = 0[/tex]

[tex] 1) {3}^{0} = 1\\ { 3 }^{3x - 1} = 1 \\ {3}^{3x - 1} = {3}^{0} \\ 3x - 1 = 0 \\ 3x = 1 \\ x = \frac{1}{3} [/tex]