kerjakan soal berikut dengan metode eliminasi dan suptitusi 2X+1Y+1Z=4700 1X+2Y+1Z=4300 3X+2Y+1Z=7100

2x + y + z = 4700 x 2
x + 2y+ z = 4300 x 1

4x + 2y + 2z = 9400
x + 2y + z = 4300
________________ -
3x + z = 5100


x + 2y + z = 4300
3x+ 2y + z = 7100
_______________ -
-2x = -2800
-x = -1400
x = 1400

3x + z = 5100
3(1400) + z = 5100
4200 +z = 5100
z = 5100-4200
z = 900

2x+ y + z = 4700
2(1400) + y + 900 = 4700
2800 + y + 900 = 4700
y = 4700-2800-900
y = 1000