persamaan linier melalui (2,-5) dan (-1,3) adalah

[tex]\displaystyle \frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1} \\ \frac{y-(-5)}{3-(-5)}=\frac{x-2}{-1-2} \\ \frac{y+5}{8}=\frac{x-2}{-3} \\ -3(y+5)=8(x-2) \\ -3y-15=8x-16 \\ 8x+3y-1=0[/tex]