Diketahui f(x) = x+2 dan g(x) = 2x^2 - 3x + 1 . Jika h(x) = ( f(x) + g(x) ) × f(x) , nilai h(-1) =

[tex]h(x) = (f(x) + g(x) ) \times f(x) \\ h(x) = (x + 2 + 2x ^{2} - 3x + 1) \times (x + 2) \\ h(x) = (2x^{2} - 2x + 3)(x + 2) \\ h(x) = 2x ^{3} + 4x {}^{2} - 2x {}^{2} - 4x + 3x + 6 \\ h(x) = 2x ^{3} + 2x {}^{2} - x + 6\\ jadi \\ h( - 1) = 2( - 1) ^{3} + 2( - 1) ^{2} - ( - 1) + 6\\ h(x) = 7[/tex]