tolong kak................

Kelas 9 Matematika
Bab Akar dan Pangkat

^ = pangkat

4] 3^(1 1/2) : ∛(1/3)
= 3^(3/2) : 3^(-1/3)
= 3^(3/2 + 1/3)
= 3^(9/6 + 2/6)
= 3^(11/6)
= 3^(1 5/6)
= 3 . ⁶√3⁵

5] (3 . p^(1 1/2))^(-4)
= (3)^(-4) . p^(3/2 . (-4))
= 1/3⁴ . p^(-6)
= 1/81 . 1/p⁶
= 1/(81 p⁶)

6] √(3³ˣ⁻¹) = (3ˣ⁻²)²
3^((3x - 1)/2) = 3^(2x - 4)
3x - 1 = 2 (2x - 4)
3x - 1 = 4x - 8
-1 + 8 = 4x - 3x
7 = x
x = 7

- Operasi Akar dan Pangkat -

4) 3^(1 1/2) : ∛(1/3) = 3^(1 1/2) : 1/3^1/3
= 3^(3/2) : 3^(-1/3)= 3^(3/2 + 1/3)
= 3^(9/6 + 2/6) = 3^(11/6) = 3^(1 5/6) = 3^1 . 3^5/6
= 3 . ⁶√3^5

5) (3 . p^(1 1/2))^(-4) = (3)^(-4) ( p^(3/2 . (-4))
= 1/3⁴ . p^(-6)
= 1/81 . 1/p^6 = 1/81p^6

6) √(3^3x-1) = (3^x-2)²
3^((3x - 1)/2) = 3^(2x-4)
3x-1 /2= (2x-4)
3x-1 = 4x-8
3x-4x = -8+1
-x = -7
x = 7

semoga membantu
-vin