Tolong kak ..........................

Mapel : Matematika
Bab : Akar dan Pangkat

1]

[tex]( \sqrt[3]{5 ^{2} } ) ^{5} \\ = 5^{ \frac{2}{3}(5) } \\ = 5 ^{ \frac{10}{3} } \\ = \sqrt[3]{5 ^{10} } \\ = \sqrt[3]{5 ^{9} \times 5 } \\ = 5 ^{3} \sqrt[3]{5} \\ = 125 \sqrt[3]{5} [/tex]

2]

[tex]( \sqrt[5]{4 ^{2} } ) ^{ - 3} \\ = \frac{1}{( \sqrt[5]{4 ^{2} }) ^{3} } \\ = \frac{1}{ \sqrt[5]{4 ^{2(3)} } } \\ = \frac{1}{ \sqrt[5]{4 ^{6} } } \\ = \frac{1}{ \sqrt[5]{4 ^{5} \times 4 } } \\ = \frac{1}{4 \sqrt[5]{4} } \\ = \frac{1}{4 \sqrt[5]{4} } \times \frac{ \sqrt[5]{8} }{ \sqrt[5]{8} } \\ = \frac{ \sqrt[5]{8} }{4 \sqrt[5]{32} } \\ = \frac{ \sqrt[5]{8} }{(4 \times 2)} \\ = \frac{ \sqrt[5]{8} }{8} [/tex]

3]

[tex]6 ^{ \frac{1}{2} } \times 6 ^{1 \frac{1}{2} } \\ = 6 ^{ \frac{1}{2} } \times 6 ^{ \frac{3}{2} } \\ = 6 ^{ \frac{1}{2} + \frac{3}{2} } \\ = 6 ^{ \frac{4}{2} } \\ = 6 ^{2} \\ = 36[/tex]

Maaf Kalau Salah