daritadi nyari jawaban ini ga ketemu hasil, ada yang tau?

[tex] \frac{ {a}^{ - 2} {b}^{2} {c}^{3} }{ ({16 {a}^{5} {b}^{ - 3} {c}^{ - 6}})^{ - 1} } \\ = \frac{ {a}^{ - 2} {b}^{2} {c}^{3}}{ ({2}^{4} {a}^{5} {b}^{ - 3} {c}^{ - 6})^{ - 1} } \\ = \frac{ {a}^{ - 2} {b}^{2} {c}^{3} }{ {2}^{ - 4} {a}^{ - 5} {b}^{3}{c}^{6} } \\ = \frac{1}{ {2}^{ - 4} } {a}^{ - 2 - ( - 5)} {b}^{2 - 3} {c}^{3 - 6} \\ = \frac{1}{ {2}^{ - 4} } {a}^{3} {b}^{ - 1} {c}^{ - 3} \\ = \frac{ {a}^{3} { b}^{ - 1} {c}^{ - 3}}{ {2}^{ - 4} } \\ = \frac{ {a}^{3} {2}^{4} }{ {b}^{1} {c}^{3} } \\ = \frac{ {2}^{4} {a}^{3} }{b {c}^{3} } [/tex]
[tex]a = \frac{1}{8} = \frac{1}{ {2}^{3} } = {2}^{ - 3} \\ b = 2 \\ c = \frac{1}{4} = \frac{1}{ {2}^{2} } = {2}^{ - 2} [/tex]
[tex] \frac{ {2}^{4} {a}^{3} }{b {c}^{3} } = \frac{ {2}^{4} ( {2}^{ - 3})^{3} }{2 { ({2}^{ - 2}) }^{3} } = \frac{ {2}^{4}. {2}^{ - 9} }{2. {2}^{ - 6} } \\ = \frac{ {2}^{4 + ( - 9)} }{ {2}^{1 + ( - 6)} } = \frac{ {2}^{ - 5} }{ {2}^{ - 5} } = 1[/tex]
Semoga dapat dipahami