perbandingan Energi diatas adalah?

mA=mB
VA= 12 m/s
VB= 6 m/s

berdasarkan pengerjaan,
EkA : EkB = 4 : 1

jawaban D.
[tex]ek = \frac{1}{2} m{v}^{2} \\ \frac{eka}{ekb} = \frac{1 \div 2 \times m \times {12}^{2} }{1 \div 2 \times m \times {6}^{2} } = ( {\frac{12}{6} ) }^{2} = {2}^{2} = 4 = \frac{4}{1}[/tex]