tentukan pers. fungsi kuadrat yang melalui titik (6,0) (2,0) dan (1,5)

kira kira seperti ini jawaban nya, semoga membantu

y = ax^2 + bx + c

(2,0)
2 = a(0)^2 + b(0) + c
2 = c

(1,5)
5 = a(1)^2 + b(1) + c
5 = a + b + 2
3 = a + b
b = 3 - a

(6,0)
0 = a(6)^2 + b(6) + c
0 = 36a + 6b + 2
-2 = 36a + 6b
-1 = 18a + 3(3-a)
-1 = 18a + 9 -3a
-10 = 15a
a = -10/15
= -2/3
b = 11/3
c = 2

y = -2/3 x^2 + 11/3 x + 2