dilarutkan 3,3g NH2OH (MR=33) dalam satu liter air sehingga diperoleh larutan dengan PH=10 berapa KB NH2OH

mol (n) = massa / Mr
n = 3,3 / 33
n = 0,1 = 10^-1 mol

M = n / volume
M = 10^-1 / 1 = 10^-1 M

pH = 10
pOH = 4
[OH-] = 10^-4 M

Kb = [OH-]^2 / M
Kb = (10^-4)^2 / 10^-1
Kb = 10^-8 / 10^-1
Kb = 10^-7