[tex]a. \sqrt{32 } - 3 \sqrt{2} + \sqrt{98} = \\ b.5 \sqrt{45} + \sqrt{80} - 2 \sqrt{125 } = \\ c.5 \sqrt{6} \times 2 \sqrt{8} - 8 \sqrt{3} = [/tex
Matematika
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Pertanyaan
[tex]a. \sqrt{32 } - 3 \sqrt{2} + \sqrt{98} = \\ b.5 \sqrt{45} + \sqrt{80} - 2 \sqrt{125 } = \\ c.5 \sqrt{6} \times 2 \sqrt{8} - 8 \sqrt{3} = [/tex]
tolong jawab yahh
1 Jawaban
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1. Jawaban riskiapis50456ou9aji
A||
√32 - 3√2 + √98
= √16 . √2 - 3√2 + √49 . √2
= 4√2 - 3√2 + 7√2
= 8√2
B||
5√45 + √80 - 2√125
= 5 √9 √5 + √16 . √5 - 2 √25 . √5
= 15 √5 + 4 √5 - 10 √5
= 9√5
C||
5√6 x 2√8 - 8√3
= 10 √48 - 8√3
= 10 √16 . √3 - 8 √ 3
= 40 √3 - 8 √3
= 32 √3