Jika x = 3 dan y = 2, tentukan nilai dari: a. (2x2 – 3x + 2) + (4x2 – 5x + 1) b. (2x + 3)(3x – 2) c. 3x2y5 : x2y2 : xy2 d. (2x – 4)5

x = 3
y = 2

jawab :

a) (2x² -3x +2)+(4x² -5x +1)
= (2(3²) - 3(3)+2) + (4(3²) -5(3) +1)
= (18 - 9 + 2) + (36 - 15 + 1)
= 11 + 22
= 33

b) (2x+3)(3x-2)
= (2(3) + 3) (3(3) - 2)
= (9)(7)
= 63

c) 3x²y^5 : x²y² : xy²
= 3(3²)(2^5) : (3²)(2²) : (3)(2²)
= 3 × 9 × 32 : 9 × 4 : 3 × 4
= 864 : 36 : 12
= 864 : 3
= 288

d) (2x-4)^5
= (2(3)-4)^5
= (2)^5
= 32

semoga membantu ya gan.........

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