Matematika

Pertanyaan

matematika wajib
kelas x
bab trigonometri
matematika wajib kelas x bab trigonometri

1 Jawaban

  • a)
    panjang sisi miring = √(12² + 9²) = √(144 + 81) = √225 = 15

    sin a = de/mi = 12/15
    cos a = sa/mi = 9/15
    tan a = de/sa = 12/9
    cosec a = 1/sina = 15/12
    sec a = 1/cosa = 15/9
    cotan a = 1/tana = 9/12

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    b.
    panjang sisi miring = √((-9)²+2²) = √(81 + 4) = √85

    sin a = de/mi = 9/√85
    cos a = sa/mi = 2/√85
    tan a = de/sa = 9/2
    cosec a = √85/9
    sec a = √85/2
    cotan a = 2/9

    Itu nilai negatifnya jadi positif karena sudutnya lancip, nilai trigonometrinya positif semua.