Tentukan hasil perpangkatan bentuk aljabar berikut. a. (2a)2 b. (3xy)3 c. (–2ab)4 d. (4a2b2)2 e. –3(x2y)3 f. –(2pq)4 g. ½(2xy)2 h. a(ab2)3

[tex]a. \: {(2)}^{2} {(a)}^{2} \\ = 4 {a }^{2} \\ \\ b. {(3)}^{3} {(x)}^{3} {(y)}^{3} \\ = 27 {x}^{ 3} {y}^{3} \\ \\ c.( { - 2)}^{4} {a}^{4} {b}^{4} \\ = 16 {a}^{4} {b}^{4} \\ \\ d. {(4)}^{2} { ({a}^{2}) }^{2} { ({b}^{2}) }^{2} \\ = 16 {a}^{4} {4b}^{4} \\ \\ e. - 3(( { {x}^{2}) }^{3} ({y})^{3} \\ = - 3 {x}^{6} - 3 {y}^{3} \\ \\ f. - (( {2)}^{4} {p}^{4} {q}^{4} ) \\ = - 16{p}^{4} {q}^{4} \: \\ \\ g. \frac{1}{2}( {2}^{2} {x}^{2} {y}^{2} ) \\ = \frac{1}{2}({4x}^{2} {y}^{2}) \: = 2 \frac{1}{2} {x}^{2} \frac{1}{2} {y}^{2} \\ \\ h.a(a {b}^{2} ) ^{3} \\ = a( {a}^{3} {b}^{6} ) \\ = {a}^{4} a {b}^{6} [/tex]
= {a}^{5} {b}^{6}