pergunakan rumus ABC untuk menyelesaikan setiap persamaan kuadrat a. X² + 6x + 8=0 b. 2x - 11x + 12 =0

caranya... cek bawah...
[tex]1. \\ x1.x2 = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac } }{2a} = \frac{ - 6 \frac{ + }{} \sqrt{ {6}^{2} - 4 \times 1 \times 8} }{2 \times 1} \\ = \frac{ - 6 \frac{ + }{} \sqrt{4} }{2} = - \frac{6 \frac{ + }{} 2}{2} \\ x1 = \frac{ - 6 + 2}{2} = - 2\\ x2 = \frac{ - 6 - 2}{2} = - 4[/tex]
[tex]rumus \: sama \\ x1.x2 = \frac{ - ( - 11) \frac{ + }{} \sqrt{ { - 11}^{2} - 4 \times 2 \times 12} }{2 \times 2} \\ = \frac{11 \frac{ + }{} \sqrt{121 - 96} }{4} = \frac{11 \frac{ + }{} \sqrt{25} }{4} = \frac{11 \frac{ + }{}5 }{4} \\ x1 = \frac{11 + 5 }{4} = 4 \\ x2 = \frac{11 - 5}{4} = \frac{6}{4} = \frac{3}{2} [/tex]