tentukan nilai n jika [tex]3 + {3}^{2} + {3}^{3} + ... + {3}^{n} = 1092[/tex]
Matematika
tarishayudia127
Pertanyaan
tentukan nilai n jika
[tex]3 + {3}^{2} + {3}^{3} + ... + {3}^{n} = 1092[/tex]
[tex]3 + {3}^{2} + {3}^{3} + ... + {3}^{n} = 1092[/tex]
1 Jawaban
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1. Jawaban Anonyme
jawab
a= 3
r = 3
sn = 1092
a (r^n - 1)/ (r - 1) = 1092
3 (3^n - 1)/ (2) = 1092
3 (3^n - 1) = 2 (1092)
3(3^n - 1)= 2.184
3^n - 1 = (2.184)/3
3^n - 1 = 728
3^n = 728 + 1
3^n = 729 = 3^6
n = 6