tolong bantu jawab trigonometri

a) P ( 1, 1 )
r = akar (1^2 + 1^2)
r = akar 2
sin P = 1/akar 2 = (1/2)akar 2
cos P = 1/akar 2 = (1/2)akar 2
tan P = 1/1 = 1
b) P ( -2akar3, -2)
r^2 = (-2akar3)^2 +(-2)^2
r^2 = 12 + 4
r^2 = 16
r = 4
cos P = -2akar3/4 = (-1/2)akar 3
sin P = -2/4 = -1/2
tan P = -2/-2akar 3 = 1/akar 3 = (1/3)akar
c) P ( -3, 3)
r^2 = (-3)^2 + (3)^2
r^2 = 9 + 9 = 18
r = 3akar 2
sin P = 3/3akar 2
= 1/akar 2 = (1/2)akar 2
cos P = -3/3akar 2
= -1/akar 2
= (-1/2)akar 2
tan P = 3/-3 = -1
d) P (-3, -1)
r^2 = (-3)^2 + (-1)^2
r^2= 10
r = akar 10
sin P = -1/akar 10 = (-1/10)akar 10
cos P = -3/akar 10 = (3/10)akar 10
tan P = -1/-3 = 1/3
e) P (-1, akar 3)
r^2 = (-1)^2 + (akar 3)^2
r^2 = 4
r = 2
sin P = akar 3 / 2
cos P = -1/2
tan P = akar 3/-1 = - akar 3