bentuk sederhana (ab^2)^-1 dikali (a^5b^8)

[Eksponen]

(ab²)-¹ . (a^5 b^8)
= 1/(ab²) . (a^5 b^8)
= a^(5 - 1) b^(8 - 2)
= a^4 b^6

[tex](a {b}^{2} )^{ - 1} \times ( {a}^{5} {b}^{8} ) \\ = {a}^{ - 1 + 5} .{b}^{ - 2 + 8} \\ = {a}^{4} {b}^{6}[/tex]