Larutan Ca(OH)2 ph 12 + log 1 dibuat dengan larutkan Ca (oh)2 (Mr=74) dalam 2Liter air. Berapa gram massa Ca(oh)2 yg dilarutkan?

log1 = 0

pH = 12
pOH = 2
[OH-] = 10^-2 M

Ca(OH)2 dianggap asam kuat bervalensi 2

[OH-] = 2 x M basa
10^-2 = 2 x M basa
5 x 10^-3 = M basa

Mr Ca(OH)2 = 74

M basa = massa basa / (volume x Mr)
5 x 10^-3 = massa basa / (2 x 74)
massa basa = 0,74 gr