Matematika

Pertanyaan

1 per √4 pangkat x+1=16

1 Jawaban


  • [tex] \frac{1}{ \sqrt{ {4}^{x + 1} }} = 16 [/tex]
    [tex]\frac{1}{ ({4}^{x + 1})^{2} } = 16 [/tex]
    [tex]\frac{1}{ {4}^{2x + 2} } = {4}^{2} [/tex]
    [tex]{4}^{ - 2x - 2} = {4}^{2} \\ - 2x - 2 = 2 \\ - 2x = 4 \\ x = \frac{4}{ - 2} \\ x = - 2[/tex]



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