berapa nilai x? [tex] {2}^{3x - 6} = 8[/tex] [tex] {9}^{x + 2} = {27}^{x - 4} [/tex] [tex] \sqrt{ {27}^{2x - 3} } = 9[/tex]

jawab

1)
2^(3x-6)= (2)^3
3x -6 =  3
3x = 9
x= 3


2)
(3)^(x+2) = (3^3)^(x- 4)

x + 2 = 3(x - 4)
x + 2 = 3x - 12
-2x = -14
x= - 7

3)
(3^3)^1/2(2x-3) = (3)(2

3 (1/2 )(2x - 3) = 2
3/2 ( 2x - 3) = 2 ....kalikan 2
3(2x - 3)= 4
6x - 9  =  4
6x = 13
x = 13/6